Tuliskan output dari program pseudo code di bawah ini.
var a: array[0..15] of integer = (1, 0, 2, 0, 4, 0, 3, 2, 6, 2, 5, 3, 7, 3, 6, 5); b: array[0..7] of integer = (4, 1, 8, 12, 5, 14, 15, 13); c: array[0..15] of integer = (-1, -1, 0, -1, 2, -1, 3, -1, 6, -1, 7, -1, 10, -1, 11, 9); d: array[0..7] of integer = (-1, -1, -1, -1, -1, -1, -1, -1); procedure kemanamana(y, z: integer); var e: integer; begin e := b[y]; d[y] := z; while(e > -1) do begin if(d[a[e]] = -1) then kemanamana(a[e], z + 1); e := c[e]; end; end; begin kemanamana(0, 0); writeln(d[7]); end.